- ..clause 1..: Basic knowledge
- ..clause 2..: Program readout
- Memo
- ..clause 4..: Description type
- ..clause 5..: Basic knowledge(example solution)
- ..clause 6..: Program readout(example solution)
- Memo(example solution)
- ..clause 8..: Description type(example solution)
[ 1-1 ]
What is called naming the name to the memory that memorizes the numerical value?
[ 1-2 ]
What is called the memory of the numerical value in the above-mentioned place?
Example solution
[ 1-2 ]
What is called only one expanding the numerical value of the above-mentioned place?
Example solution
[ 2-1 ]
How are you displayed when the following program is executed?
#include <stdio.h> int main(void) { int x,y; x = 10; y = x * 10 + 20; printf("%5d\n",y); return 0; }
Example solution
[ 3-1 ]
Buy one soft drink of 198 yen each and 2 glasses of milk of 138 yen each.
Request fishing when it pays by the thousand yen bill.
However, the consumption tax of 5% is added, and the fished amount is assumed to be an integer.
It is assumed whether the half-adjust of the consumption tax to be free.
Example solution
[ 4-1 ]
3.14 * When calculating as 12 according to the real number and the integer
Describe the reason concisely though the answer is treated as a real number.
[ 1-1 ]
Variable declaration
- Even only the variable is a correct answer.
[ 1-2 ]
Substitution
Problem
[ 1-3 ]
Increment
Problem
[ 2-1 ]
- The space of two digits enters the previous part because it is %5d specification.
120
Problem
[ 3-1 ]
#include <stdio.h> int main(void) { int juice,milk,money,payment,change; double tax; juice = 198; milk = 138; money = 1000; tax = 1.05; payment = (int)((juice + milk * 2) * tax); change = money - payment; Printf ("%d yen \n" change); return 0; }
- The change is easy later though you may not use the variable and solve it if it uses it.
503 yen
- When the casting conversion has been forgotten, it is assumed that it gives a demerit mark.
- When the answer is made a real number, it is assumed that it gives a demerit mark.
- The answer is slightly different according to the computational method.
Problem
[ 4-1 ]
To prevent the numerical value below the decimal point being rounded down.