{"id":2095,"date":"2025-12-24T17:18:41","date_gmt":"2025-12-24T08:18:41","guid":{"rendered":"https:\/\/math-travel.com\/?p=2095"},"modified":"2026-02-11T16:26:59","modified_gmt":"2026-02-11T07:26:59","slug":"sincoskousiki","status":"publish","type":"post","link":"https:\/\/math-travel.jp\/math-1\/sincoskousiki\/","title":{"rendered":"\u4e09\u89d2\u6bd4\u306e\u76f8\u4e92\u95a2\u4fc2\u3092\u4f7f\u3044\u3053\u306a\u305d\u3046\uff013\u3064\u306e\u91cd\u8981\u516c\u5f0f\u3068\u8a08\u7b97\u3092\u30b9\u30d4\u30fc\u30c9\u30a2\u30c3\u30d7\u3055\u305b\u308b\u30b3\u30c4"},"content":{"rendered":"\n

\u6570\u5b66\u2160\u4e09\u89d2\u6bd4\u306e\u306a\u304b\u3067\u3082\u300c\u4e09\u89d2\u6bd4\u306e\u76f8\u4e92\u95a2\u4fc2\u300d\u306f\u304b\u306a\u308a\u91cd\u8981\u306a\u516c\u5f0f<\/span>\u3067\u3059\u3002<\/span><\/p>\n\n\n\n

\u4eca\u56de\u89e3\u6c7a\u3059\u308b\u60a9\u307f<\/span><\/div>
\n

\u300c\u4e09\u89d2\u6bd4\u306e\u76f8\u4e92\u95a2\u4fc2\u3063\u3066\u306a\u3093\u3060\u3063\u3051\uff1f\u300d <\/p>\n\n\n\n

\u300c\u3069\u3046\u3084\u3063\u3066\u4f7f\u3046\u3093\u3060\u3063\u3051\uff1f\u300d<\/p>\n<\/div><\/div>\n\n\n

\"\"\u9ad8\u6821\u751f<\/span><\/div>
\n

\u4e09\u89d2\u6bd4\u304c\u3068\u3063\u3066\u3082\u82e6\u624b\u3067\u3059\u2026<\/p>\n<\/span><\/span><\/span><\/div><\/div><\/div><\/div>\n\n\n

\u672c\u8a18\u4e8b\u3067\u306f\u3001\u4e09\u89d2\u6bd4\u306e\u76f8\u4e92\u95a2\u4fc2<\/span>\u306b\u3064\u3044\u3066\u307e\u3068\u3081\u3066\u3044\u304d\u307e\u3059\u3002<\/p>\n\n\n\n

\u4e09\u89d2\u6bd4\u306e\u5358\u5143\u306b\u306f\u91cd\u8981\u516c\u5f0f\u304c\u591a\u304f\u3042\u308a\u307e\u3059\u304c\u3001\u305d\u306e\u4e2d\u3067\u3082\u4e09\u89d2\u6bd4\u306e\u76f8\u4e92\u95a2\u4fc2\u306f\u5fc5\u305a\u899a\u3048\u3066\u6b32\u3057\u3044\u516c\u5f0f<\/span>\u3067\u3059\u3002<\/p>\n\n\n\n

\u4e09\u89d2\u6bd4\u306e\u76f8\u4e92\u95a2\u4fc2<\/span><\/div>
\n

\\(\\sin^{2} \\theta+\\cos^{2} \\theta = 1\\)
\\(\\displaystyle \\tan \\theta = \\frac{\\sin \\theta}{\\cos \\theta}\\)
\\(\\displaystyle 1+\\tan ^{2} \\theta = \\frac{1}{\\cos ^{2} \\theta}\\)<\/p>\n<\/div><\/div>\n\n\n\n

\u3053\u306e\u76f8\u4e92\u95a2\u4fc2\u306f\u6570\u2161\u306e\u300c\u4e09\u89d2\u95a2\u6570\u300d\u3067\u3082\u4f7f\u3046\u306e\u3067\u3001\u3053\u306e\u6a5f\u4f1a\u306b\u5fc5\u305a\u899a\u3048\u307e\u3057\u3087\u3046\u3002<\/span><\/p>\n\n\n

\"\"\u9ad8\u6821\u751f<\/span><\/div>
\n

\u3067\u3082\u899a\u3048\u3065\u3089\u3044\u3057,\u4f7f\u3044\u65b9\u3082\u3088\u304f\u5206\u304b\u3089\u306a\u3044\u3067\u3059\u2026<\/p>\n<\/span><\/span><\/span><\/div><\/div><\/div><\/div>\n\n\n

\u3068\u306f\u3044\u3048\u3001\u521d\u3081\u306f\u4f7f\u3044\u65b9\u3082\u3088\u304f\u5206\u304b\u3089\u306a\u3044\u3067\u3059\u3088\u306d\u3002\u307c\u304f\u3082\u5b8c\u74a7\u306b\u899a\u3048\u3089\u308c\u308b\u307e\u3067\u306f\u4f55\u5ea6\u3082\u8abf\u3079\u3066\u307e\u3057\u305f<\/p>\n\n\n\n

\u672c\u8a18\u4e8b\u3067\u306f\u4e09\u89d2\u6bd4\u306e\u76f8\u4e92\u95a2\u4fc2\u3092\u4e01\u5be7\u306b\u89e3\u8aac\u3057\u3066\u3044\u308b<\/span>\u306e\u3067\u305c\u3072\u6700\u5f8c\u307e\u3067\u3054\u89a7\u304f\u3060\u3055\u3044\u3002<\/p>\n\n\n

\"\"\u30b7\u30fc\u30bf<\/span><\/div>
\n

\u6c17\u306b\u306a\u308b\u898b\u51fa\u3057\u3092\u30af\u30ea\u30c3\u30af\u3057\u3066\u3001
\u305c\u3072\u6700\u5f8c\u307e\u3067\u3054\u89a7\u304f\u3060\u3055\u3044\u3002<\/p>\n<\/span><\/span><\/span><\/div><\/div><\/div><\/div>\n\n\n

\u4e09\u89d2\u6bd4\u306e\u76f8\u4e92\u95a2\u4fc2<\/h2>\n\n\n\n

\u4e09\u89d2\u6bd4\u306e\u76f8\u4e92\u95a2\u4fc2\u306f\u5fc5\u305a\u62bc\u3055\u3048\u3066\u304a\u304d\u305f\u3044\u91cd\u8981\u306a\u516c\u5f0f<\/span>\u3067\u3059\u3002<\/span><\/p>\n\n\n\n

\u4e09\u89d2\u6bd4\u306e\u76f8\u4e92\u95a2\u4fc2<\/span><\/div>
\n

\\(\\sin^{2} \\theta+\\cos^{2} \\theta=1\\)
\\(\\displaystyle \\tan \\theta=\\frac{\\sin \\theta}{\\cos \\theta}\\)
\\(\\displaystyle 1+\\tan ^{2} \\theta=\\frac{1}{\\cos ^{2} \\theta}\\)<\/p>\n<\/div><\/div>\n\n\n\n

\u4e09\u89d2\u6bd4\u306e\u76f8\u4e92\u95a2\u4fc2\u3092\u4f7f\u3046\u30e1\u30ea\u30c3\u30c8\u3068\u3057\u3066\u306f\u3001sin,cos,tan\u306e\u3069\u308c\u304b1\u3064\u304c\u5206\u304b\u308c\u3070\u4ed6\u306e\u5168\u3066\u3092\u6c42\u3081\u308b\u3053\u3068\u304c\u3067\u304d\u308b\u3053\u3068\u3067\u3059\u3002<\/span><\/p>\n\n\n

\"\"\u9ad8\u6821\u751f<\/span><\/div>
\n

\u3048\uff011\u3064\u5206\u304b\u308c\u3070\u5168\u90e8\u5206\u304b\u308b\u306e!?<\/p>\n<\/span><\/span><\/span><\/div><\/div><\/div><\/div>\n\n

\"\"\u30b7\u30fc\u30bf<\/span><\/div>
\n

\u3068\u3066\u3082\u4fbf\u5229\u3060\u304b\u3089\u5fc5\u305a\u899a\u3048\u3088\u3046\uff01<\/p>\n<\/span><\/span><\/span><\/div><\/div><\/div><\/div>\n\n\n

\u305d\u308c\u3067\u306f\u4e09\u89d2\u6bd4\u306e\u76f8\u4e92\u95a2\u4fc2\u306e\u4f7f\u3044\u65b9\u306b\u3064\u3044\u3066\u89e3\u8aac\u3057\u3066\u3044\u304d\u307e\u3059\u3002<\/p>\n\n\n\n

\u4e09\u89d2\u6bd4\u306e\u76f8\u4e92\u95a2\u4fc2\u3000\u4f7f\u3044\u65b9<\/h2>\n\n\n
\"\"\u9ad8\u6821\u751f<\/span><\/div>
\n

\uff13\u3064\u306e\u516c\u5f0f\u304c\u5927\u4e8b\u306a\u306e\u306f\u5206\u304b\u3063\u305f\u3051\u3069\u3001\u3069\u3046\u3084\u3063\u3066\u4f7f\u3046\u306e\uff1f<\/p>\n<\/span><\/span><\/span><\/div><\/div><\/div><\/div>\n\n\n

\u4e09\u89d2\u6bd4\u306e\u76f8\u4e92\u95a2\u4fc2\u3092\u4f7f\u3063\u3066\u5b9f\u969b\u306b\u5404\u5024\u3092\u6c42\u3081\u3066\u307f\u307e\u3057\u3087\u3046\u3002<\/p>\n\n\n\n

\u4e0b\u90e8\u306b\u4f8b\u984c3\u3064\u3092\u7528\u610f\u3057\u305f\u306e\u3067\u305d\u308c\u305e\u308c\u306e\u4f7f\u3044\u65b9\u3092\u78ba\u8a8d\u3057\u3066\u304f\u3060\u3055\u3044\u3002<\/p>\n\n\n\n

\\(\\sin^{2} \\theta+\\cos^{2} \\theta=1\\)<\/h3>\n\n\n\n

\u3053\u306e\u516c\u5f0f\u306f\u3001\\(\\sin \\theta\\)\u3082\u3057\u304f\u306f\\(\\cos \\theta\\)\u304c\u5206\u304b\u308b\u3068\u304d\u306b\u4f7f\u3046\u516c\u5f0f\u3067\u3059\u3002<\/p>\n\n\n\n

\u4f8b\u3048\u3070\\(\\theta\\)\u304c\u92ed\u89d2\u3067\\(\\displaystyle \\sin \\theta=\\frac{1}{3}\\)\u3060\u3068\u3057\u307e\u3057\u3087\u3046\u3002<\/p>\n\n\n\n

\u3053\u306e\u3068\u304d\u4e09\u89d2\u6bd4\u306e\u76f8\u4e92\u95a2\u4fc2\u2460\u3092\u7528\u3044\u3066\u3001<\/p>\n\n\n\n

\\[\\sin^{2} \\theta+\\cos^{2} \\theta=1\\]<\/p>\n\n\n\n

\\[\\displaystyle (\\frac{1}{3})^{2}+\\cos^{2} \\theta=1\\]<\/p>\n\n\n\n

\\[\\displaystyle \\frac{1}{9}+\\cos^{2} \\theta=1\\]<\/p>\n\n\n\n

\\[\\displaystyle \\cos^{2} \\theta=\\frac{8}{9}\\]<\/p>\n\n\n\n

\u3053\u306e\u3088\u3046\u306b\\(\\cos\\)\u306e\u5f0f\u306b\u3059\u308b\u3053\u3068\u304c\u3067\u304d\u307e\u3057\u305f\u3002<\/p>\n\n\n\n

\u3053\u3053\u3067\u3001\\(\\cos \\theta\\)\u3092\u6c42\u3081\u308b\u969b\u306b\u7b26\u53f7\u306e\u6b63\u8ca0<\/span>\u306b\u6c17\u3092\u4ed8\u3051\u307e\u3057\u3087\u3046\u3002<\/p>\n\n\n\n

\u4eca\u56de\u306f\\(\\theta\\)\u304c\u92ed\u89d2\u306a\u306e\u3067\u3001\\(\\cos \\theta > 0\\)<\/p>\n\n\n\n

\\[\\displaystyle \\cos \\theta=\\frac{2\\sqrt{2}}{3}\\]<\/p>\n\n\n\n

\\(\\sin \\theta\\)\u3082\u3057\u304f\u306f\\(\\cos \\theta\\)\u304c\u5206\u304b\u308b\u3068\u304d\u306f\u76f8\u4e92\u95a2\u4fc2\u2460\u3092\u7528\u3044\u308b\u3053\u3068\u3067\u3001\u3082\u3046\u4e00\u65b9\u3082\u6c42\u3081\u308b\u3053\u3068\u304c\u3067\u304d\u307e\u3059\u3002<\/p>\n\n\n\n

\\(\\displaystyle \\tan \\theta=\\frac{\\sin \\theta}{\\cos \\theta}\\)<\/h3>\n\n\n\n

\u76f8\u4e92\u95a2\u4fc2\u2460\u306e\u516c\u5f0f\u3067\\(\\sin \\theta,\\cos \\theta\\)\u3092\u6c42\u3081\u305f\u5f8c\u306b\\(\\tan \\theta\\)\u3092\u6c42\u3081\u307e\u3057\u3087\u3046\u3002<\/p>\n\n\n\n

\\(\\displaystyle \\sin \\theta=\\frac{1}{3}\\),\\(\\displaystyle \\cos \\theta=\\frac{2\\sqrt{2}}{3}\\)\u306e\u3068\u304d\u3001<\/p>\n\n\n\n

\\begin{eqnarray}
\\displaystyle \\tan \\theta &=& \\frac{\\sin \\theta}{\\cos \\theta}\\\\
\\displaystyle &=& \\frac{\\frac{1}{3}}{\\frac{2\\sqrt{2}}{3}}\\\\
\\displaystyle &=& \\frac{1}{3} \u00d7 \\frac{3}{2\\sqrt{2}}\\\\
\\displaystyle &=& \\frac{1}{2\\sqrt{2}}\\\\
\\displaystyle &=& \\frac{\\sqrt{2}}{4}
\\end{eqnarray}<\/p>\n\n\n\n

\u9006\u306b\\(\\tan \\theta\\)\u3068\\(\\sin \\theta\\)\u304c\u5206\u304b\u3063\u3066\u3044\u3066\u3001\\(\\cos \\theta\\)\u3092\u6c42\u3081\u308b\u30d1\u30bf\u30fc\u30f3\u3082\u3042\u308a\u307e\u3059\u3002<\/p>\n\n\n\n

\u516c\u5f0f\u3092\u6697\u8a18\u3059\u308b\u3060\u3051\u3067\u306a\u304f\u3001\u5f0f\u3092\u5909\u5f62\u3057\u3066\u4f7f\u3044\u3053\u306a\u305b\u308b\u3088\u3046\u306b\u6163\u308c\u3066\u3044\u304d\u307e\u3057\u3087\u3046\uff01<\/p>\n\n\n\n

\\(\\displaystyle 1+\\tan ^{2} \\theta=\\frac{1}{\\cos ^{2} \\theta}\\)<\/h3>\n\n\n\n

\u3053\u306e\u516c\u5f0f\u306f\\(\\tan \\theta\\)\u3082\u3057\u304f\u306f\\(\\cos \\theta\\)\u304c\u5206\u304b\u308b\u6642\u306b\u4f7f\u3046\u516c\u5f0f\u3067\u3059\u3002<\/p>\n\n\n\n

\\(\\theta\\)\u304c\u92ed\u89d2\u3067\u3001\\(\\displaystyle \\tan \\theta=\\frac{\\sqrt{2}}{4}\\)\u306e\u3068\u304d\u3001<\/p>\n\n\n\n

\\begin{eqnarray}
\\displaystyle 1+\\tan ^{2} \\theta &=& \\frac{1}{\\cos ^{2} \\theta}\\\\
\\displaystyle 1+\\frac{2}{16} &=& \\frac{1}{\\cos ^{2} \\theta}\\\\
\\displaystyle \\frac{9}{8} &=& \\frac{1}{\\cos ^{2} \\theta}\\\\
\\displaystyle \\cos ^{2} \\theta &=& \\frac{8}{9}
\\end{eqnarray}<\/p>\n\n\n\n

\\(\\theta\\)\u304c\u92ed\u89d2\u306a\u306e\u3067\u3001\\(\\cos \\theta >0\\)<\/p>\n\n\n\n

\\[\\displaystyle \\cos \\theta = \\frac{2\\sqrt{2}}{3}\\]<\/p>\n\n\n\n

\u4e09\u89d2\u6bd4\u306e\u76f8\u4e92\u95a2\u4fc2\u3000\u8a3c\u660e<\/h2>\n\n\n\n

\u4e09\u89d2\u6bd4\u306e\u76f8\u4e92\u95a2\u4fc2\u304c\u306a\u305c\u6210\u308a\u7acb\u3064\u306e\u304b\u3001\u305d\u308c\u305e\u308c\u306e\u5f0f\u3092\u8a3c\u660e\u3057\u3066\u304a\u304d\u307e\u3057\u3087\u3046\u3002<\/p>\n\n\n\n

\u8a3c\u660e\u304c\u5fc5\u8981\u306a\u3044\u65b9\u306f\u3001\u6b21\u306e\u300c\u4e09\u89d2\u95a2\u6570\u306e\u76f8\u4e92\u95a2\u4fc2\u3000\u4f7f\u3044\u65b9<\/a>\u300d\u3078\u9032\u3093\u3067\u304f\u3060\u3055\u3044\u3002<\/p>\n\n\n\n

\u4e0b\u306e\u56f3\u306e\u3088\u3046\u306a\u4e09\u89d2\u5f62\u3092\u5143\u306b\u8a3c\u660e\u3057\u3066\u3044\u304d\u307e\u3059\u3002<\/p>\n\n\n

\n
\"\u4e09\u89d2\u95a2\u6570\u306e\u76f8\u4e92\u95a2\u4fc2\u3000\u8a3c\u660e\"<\/figure>\n<\/div>\n\n\n

\u76f8\u4e92\u95a2\u4fc2\u2460\\(\\sin^{2} \\theta+\\cos^{2} \\theta=1\\)<\/h3>\n\n\n\n
\u4e09\u89d2\u6bd4\u306e\u76f8\u4e92\u95a2\u4fc2\u2460<\/span><\/div>
\n

\\(\\sin^{2} \\theta+\\cos^{2} \\theta = 1\\)<\/p>\n<\/div><\/div>\n\n\n\n

\u307e\u305a\u306f\\(\\sin^{2} \\theta+\\cos^{2} \\theta=1\\)\u304b\u3089\u8a3c\u660e\u3057\u3066\u3044\u304d\u307e\u3059\u3002<\/p>\n\n\n\n

\u3053\u308c\u304c\uff11\u756a\u306e\u8ef8\u3068\u306a\u308b\u516c\u5f0f\u306a\u306e\u3067\u3001\u6700\u512a\u5148\u3067\\(\\sin^{2} \\theta+\\cos^{2} \\theta=1\\)\u3092\u53e9\u304d\u8fbc\u3093\u3067\u304f\u3060\u3055\u3044\u3002<\/span><\/p>\n\n\n\n

\\(\\displaystyle \\sin \\theta=\\frac{y}{r}, \\cos \\theta=\\frac{x}{r}\\)\u3092\u5909\u5f62\u3059\u308b\u3068\u3001\u5404\u8fba\u3092\u4e0b\u56f3\u306e\u3088\u3046\u306b\u8868\u3059\u3053\u3068\u304c\u3067\u304d\u307e\u3059\u3002<\/p>\n\n\n

\n
\"\\(\\sin^{2}<\/figure>\n<\/div>\n\n\n

\u4e09\u5e73\u65b9\u306e\u5b9a\u7406\u3088\u308a\u3001<\/p>\n\n\n\n

\\[r^2=(r \\sin \\theta)^{2}+(r \\cos \\theta)^{2}\\]<\/p>\n\n\n\n

\\[r^2=r^{2} \\sin^{2} \\theta+r^{2} \\cos^{2} \\theta\\]<\/p>\n\n\n\n

\u4e21\u8fba\u3092\\(r^{2}\\)\u3067\u5272\u3063\u3066\u3001<\/p>\n\n\n\n

\\[1=\\sin^{2} \\theta+\\cos^{2} \\theta\\]<\/span><\/p>\n\n\n\n

\u3088\u3063\u3066\u3001\\(\\sin^{2} \\theta+\\cos^{2} \\theta=1\\)\u306e\u8a3c\u660e\u7d42\u4e86\u3067\u3059\u3002<\/p>\n\n\n\n

\u76f8\u4e92\u95a2\u4fc2\u2461\\(\\displaystyle \\tan \\theta=\\frac{\\sin \\theta}{\\cos \\theta}\\)<\/h3>\n\n\n\n
\u4e09\u89d2\u6bd4\u306e\u76f8\u4e92\u95a2\u4fc2\u2461<\/span><\/div>
\n

\\(\\displaystyle \\tan \\theta = \\frac{\\sin \\theta}{\\cos \\theta}\\)<\/p>\n<\/div><\/div>\n\n\n\n

\u76f8\u4e92\u95a2\u4fc2\u2460\u304c\u7406\u89e3\u3067\u304d\u305f\u65b9\u306f\u3059\u3050\u306b\u30d4\u30f3\u3068\u304d\u307e\u3059\u306d\u3002<\/p>\n\n\n\n

\u307e\u305a\u4e09\u89d2\u6bd4\u306e\u5b9a\u7fa9\u3088\u308a\u3001<\/p>\n\n\n\n

\\[\\tan \\displaystyle \\theta=\\frac{y}{x}\\]<\/p>\n\n\n\n

\u5148\u307b\u3069\u306e\u4e09\u89d2\u5f62\u306e\u56f3\u304b\u3089\u5206\u304b\u308b\u3088\u3046\u306b\\(y=r \\sin \\theta,x=r \\cos \\theta\\)\u306a\u306e\u3067\u3001<\/p>\n\n\n\n

\\begin{eqnarray}
\\tan \\displaystyle \\theta &=& \\frac{y}{x}\\\\
&=& \\displaystyle \\frac{r \\sin \\theta}{r \\cos \\theta}\\\\
&=& \\displaystyle \\frac{\\sin \\theta}{\\cos \\theta}
\\end{eqnarray}<\/p>\n\n\n\n

\u3088\u3063\u3066\u3001\\(\\displaystyle \\tan \\theta=\\frac{\\sin \\theta}{\\cos \\theta}\\)\u306e\u8a3c\u660e\u7d42\u4e86\u3067\u3059\u3002<\/p>\n\n\n\n

\u76f8\u4e92\u95a2\u4fc2\u2462\\(\\displaystyle 1+\\tan ^{2} \\theta=\\frac{1}{\\cos ^{2} \\theta}\\)<\/h3>\n\n\n\n
\u4e09\u89d2\u6bd4\u306e\u76f8\u4e92\u95a2\u4fc2\u2462<\/span><\/div>
\n

\\(\\displaystyle 1+\\tan ^{2} \\theta=\\frac{1}{\\cos ^{2} \\theta}\\)<\/p>\n<\/div><\/div>\n\n\n\n

\u76f8\u4e92\u95a2\u4fc2\u2460\u3092\u5909\u5f62\u3057\u3066\u8a3c\u660e\u3057\u307e\u3059\u3002<\/p>\n\n\n\n

\\[\\sin^{2} \\theta+\\cos^{2} \\theta=1\\]<\/p>\n\n\n\n

\u4e21\u8fba\u3092\\(\\cos^{2} \\theta\\)\u3067\u5272\u308a\u307e\u3059<\/p>\n\n\n\n

\\[\\displaystyle \\frac{\\sin^{2} \\theta}{\\cos^{2} \\theta}+\\frac{\\cos^{2} \\theta}{\\cos^{2} \\theta}=\\frac{1}{\\cos^{2} \\theta}\\]<\/p>\n\n\n\n

\\[\\displaystyle \\tan^{2} \\theta+1=\\frac{1}{\\cos^{2} \\theta}\\]<\/p>\n\n\n\n

\u3088\u3063\u3066\u3001\u8a3c\u660e\u7d42\u4e86\u3067\u3059\u3002<\/p>\n\n\n\n

\u4e09\u89d2\u6bd4\u306e\u76f8\u4e92\u95a2\u4fc2\uff1c\u7df4\u7fd2\u554f\u984c\uff1e<\/h2>\n\n\n
\n
\"\u4e09\u89d2\u95a2\u6570\u306e\u76f8\u4e92\u95a2\u4fc2\uff1c\u7df4\u7fd2\u554f\u984c\uff1e\"<\/figure>\n<\/div>\n\n\n


\u305d\u308c\u3067\u306f\u3001\u4eca\u56de\u5b66\u3093\u3060\u3053\u3068\u3092\u6d3b\u304b\u3057\u3066\u7df4\u7fd2\u554f\u984c\u3092\u89e3\u3044\u3066\u307f\u307e\u3057\u3087\u3046\u3002<\/p>\n\n\n\n

\u7df4\u7fd2\u554f\u984c\u2460<\/span><\/div>
\n

\\(\\theta\\)\u306f\u92ed\u89d2\u3068\u3059\u308b\u3002<\/p>\n\n\n\n

\\(\\displaystyle \\sin \\theta=\\frac{2}{3}\\)\u306e\u3068\u304d\u3001\\(\\cos \\theta,\\tan \\theta\\)\u306e\u5024\u3092\u6c42\u3081\u3088\u3002<\/p>\n<\/div><\/div>\n\n\n\n

\u89e3\u7b54<\/span><\/p>\n\n\n\n

\\begin{eqnarray}
\\sin^{2} \\theta+\\cos^{2} \\theta &=& 1\\\\
\\displaystyle \\left( \\frac{2}{3} \\right)^{2}+\\cos^{2} \\theta &=& 1\\\\
\\displaystyle \\frac{4}{9}+\\cos^{2} \\theta &=& 1\\\\
\\displaystyle \\cos^{2} \\theta &=& \\frac{5}{9}\\\\
\\displaystyle \\cos \\theta &=& \u00b1\\sqrt{\\frac{5}{9}}\\\\
\\displaystyle &=& \u00b1\\frac{\\sqrt{5}}{3}
\\end{eqnarray}<\/p>\n\n\n\n

\\(\\theta\\)\u304c\u92ed\u89d2\u306a\u306e\u3067\u3001\\(\\cos \\theta>0\\)\u306a\u306e\u3067\u3001<\/p>\n\n\n\n

\\[\\displaystyle \\cos \\theta=\\frac{\\sqrt{5}}{3}\\]<\/span><\/p>\n\n\n\n

\u3053\u308c\u3067\\(\\sin \\theta\\)\u3068\\(\\cos \\theta\\)\u304c\u5206\u304b\u3063\u305f\u306e\u3067\u3001\u76f8\u4e92\u95a2\u4fc2\u2461\u306e\u516c\u5f0f\u306b\u4ee3\u5165\u3057\u307e\u3057\u3087\u3046\u3002<\/p>\n\n\n\n

\\begin{eqnarray}
\\displaystyle \\tan \\theta &=& \\frac{\\sin \\theta}{\\cos \\theta}\\\\
\\displaystyle &=& \\frac{\\frac{2}{3}}{\\frac{\\sqrt{5}}{3}}\\\\
\\displaystyle &=&\\frac{2}{3} \u00d7 \\frac{3}{\\sqrt{5}}\\\\
\\displaystyle &=&\\frac{2}{\\sqrt{5}}
\\end{eqnarray}<\/p>\n\n\n\n

\u6709\u7406\u5316\u3057\u3066\u3001<\/p>\n\n\n\n

\\[\\displaystyle \\tan \\theta=\\frac{2\\sqrt{5}}{5}\\]<\/span><\/p>\n\n\n\n

\u7df4\u7fd2\u554f\u984c\u2460<\/span><\/div>
\n

\\(\\theta\\)\u306f\u92ed\u89d2\u3068\u3059\u308b\u3002<\/p>\n\n\n\n

\\(\\displaystyle \\tan \\theta=\\frac{1}{2}\\)\u306e\u3068\u304d\u3001\\(\\sin \\theta,\\cos \\theta\\)\u306e\u5024\u3092\u6c42\u3081\u3088\u3002<\/p>\n<\/div><\/div>\n\n\n\n

\u89e3\u7b54<\/span><\/p>\n\n\n\n

\\begin{eqnarray}
\\displaystyle 1+\\tan ^{2} \\theta &=& \\frac{1}{\\cos ^{2} \\theta}\\\\
\\displaystyle 1+(\\frac{1}{2})^{2} &=& \\frac{1}{\\cos ^{2} \\theta}\\\\
\\displaystyle 1+\\frac{1}{4} &=& \\frac{1}{\\cos ^{2} \\theta}\\\\
\\displaystyle \\frac{5}{4} &=& \\frac{1}{\\cos ^{2} \\theta}\\\\
\\displaystyle \\cos ^{2} \\theta &=& \\frac{4}{5}\\\\
\\displaystyle \\cos \\theta &=& \u00b1\\frac{2}{\\sqrt{5}}=\\frac{2\\sqrt{5}}{5}
\\end{eqnarray}<\/p>\n\n\n\n

\\(\\theta\\)\u306f\u92ed\u89d2\u306a\u306e\u3067\u3001<\/p>\n\n\n\n

\\[\\displaystyle \\cos \\theta=\\frac{2\\sqrt{5}}{5}\\]<\/span><\/p>\n\n\n\n

\\begin{eqnarray}
\\sin^{2} \\theta+\\cos^{2} \\theta &=&1\\\\
\\displaystyle \\sin^{2} \\theta+\\left(\\frac{2\\sqrt{5}}{5} \\right)^{2}&=&1\\\\
\\displaystyle \\sin^{2} \\theta+\\frac{20}{25}&=&1\\\\
\\displaystyle \\sin^{2} \\theta &=& \\frac{5}{25}
\\end{eqnarray}<\/p>\n\n\n\n

\\(\\theta\\)\u306f\u92ed\u89d2\u306a\u306e\u3067\u3001<\/p>\n\n\n\n

\\[\\displaystyle \\sin \\theta=\\frac{\\sqrt{5}}{5}\\]<\/span><\/p>\n\n\n\n

\u4e09\u89d2\u6bd4\u306e\u76f8\u4e92\u95a2\u4fc2\u3000\u307e\u3068\u3081<\/h2>\n\n\n\n

\u4eca\u56de\u306f\u5fc5\u305a\u899a\u3048\u305f\u3044\u91cd\u8981\u516c\u5f0f\u306e1\u3064“\u4e09\u89d2\u6bd4\u306e\u76f8\u4e92\u95a2\u4fc2”<\/span>\u3092\u89e3\u8aac\u3057\u307e\u3057\u305f\u3002<\/p>\n\n\n\n

\u4e09\u89d2\u6bd4\u306e\u76f8\u4e92\u95a2\u4fc2<\/span><\/div>
\n

\\(\\sin^{2} \\theta+\\cos^{2} \\theta=1\\)
\\(\\displaystyle \\tan \\theta=\\frac{\\sin \\theta}{\\cos \\theta}\\)
\\(\\displaystyle 1+\\tan ^{2} \\theta=\\frac{1}{\\cos ^{2} \\theta}\\)<\/p>\n<\/div><\/div>\n\n\n\n

\u7e70\u308a\u8fd4\u3057\u306b\u306a\u308a\u307e\u3059\u304c\u3001\u4e09\u89d2\u6bd4\u306e\u76f8\u4e92\u95a2\u4fc2\u306f\u5f53\u305f\u308a\u524d\u306b\u4f7f\u3048\u308b\u3088\u3046\u306b\u3057\u307e\u3057\u3087\u3046\u3002<\/p>\n\n\n\n

\u3053\u308c\u304b\u3089\u7fd2\u3046\u6570\u2161\u300c\u4e09\u89d2\u95a2\u6570\u300d\u3067\u3082\u4e09\u89d2\u6bd4\u306e\u5f0f\u5909\u5f62\u306f\u5fc5\u9808\u3067\u3059\u3002<\/p>\n\n\n\n

\u305d\u308c\u3067\u306f\u6700\u5f8c\u307e\u3067\u898b\u3066\u3044\u305f\u3060\u3044\u3066\u3042\u308a\u304c\u3068\u3046\u3054\u3056\u3044\u307e\u3057\u305f\u3002<\/p>\n\n\n\n

\u307f\u3093\u306a\u306e\u52aa\u529b\u304c\u5831\u308f\u308c\u307e\u3059\u3088\u3046\u306b\uff01<\/p>\n","protected":false},"excerpt":{"rendered":"

\u6570\u5b66\u2160\u4e09\u89d2\u6bd4\u306e\u306a\u304b\u3067\u3082\u300c\u4e09\u89d2\u6bd4\u306e\u76f8\u4e92\u95a2\u4fc2\u300d\u306f\u304b\u306a\u308a\u91cd\u8981\u306a\u516c\u5f0f\u3067\u3059\u3002 \u672c\u8a18\u4e8b\u3067\u306f\u3001\u4e09\u89d2\u6bd4\u306e\u76f8\u4e92\u95a2\u4fc2\u306b\u3064\u3044\u3066\u307e\u3068\u3081\u3066\u3044\u304d\u307e\u3059\u3002 \u4e09\u89d2\u6bd4\u306e\u5358\u5143\u306b\u306f\u91cd\u8981\u516c\u5f0f\u304c\u591a\u304f\u3042\u308a\u307e\u3059\u304c\u3001\u305d\u306e\u4e2d\u3067\u3082\u4e09\u89d2\u6bd4\u306e\u76f8\u4e92\u95a2\u4fc2\u306f\u5fc5\u305a\u899a\u3048\u3066\u6b32\u3057\u3044\u516c\u5f0f\u3067\u3059\u3002 […]<\/p>\n","protected":false},"author":1,"featured_media":12769,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"swell_btn_cv_data":"","footnotes":""},"categories":[34,222],"tags":[36,14,11],"class_list":["post-2095","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-sankakuhi","category-math-1","tag-36","tag-b","tag-11"],"yoast_head":"\n\u4e09\u89d2\u6bd4\u306e\u76f8\u4e92\u95a2\u4fc2\u3092\u4f7f\u3044\u3053\u306a\u305d\u3046\uff013\u3064\u306e\u91cd\u8981\u516c\u5f0f\u3068\u8a08\u7b97\u3092\u30b9\u30d4\u30fc\u30c9\u30a2\u30c3\u30d7\u3055\u305b\u308b\u30b3\u30c4<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/math-travel.jp\/math-1\/sincoskousiki\/\" \/>\n<meta property=\"og:locale\" content=\"ja_JP\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta 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